(2x^3y^-2/x^2y^5)^-2

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Solution for (2x^3y^-2/x^2y^5)^-2 equation: 


D( x )

((2*x^3*y^-2)/(x^2))*y^5 = 0

x^2 = 0

((2*x^3*y^-2)/(x^2))*y^5 = 0

((2*x^3*y^-2)/(x^2))*y^5 = 0

2*x*y^3 = 0 // : 2*y^3

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(((2*x^3*y^-2)/(x^2))*y^5)^-2 = 0

1/4*x^-2*y^-6 = 0 // : 1/4*y^-6

x^-2 = 0

x należy do O

x belongs to the empty set

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